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/**
* Author: Simon Lindholm
* Date: 2016-08-31
* License: CC0
* Source: http://eli.thegreenplace.net/2009/03/07/computing-modular-square-roots-in-python/
* Description: Tonelli-Shanks algorithm for modular square roots.
* Time: O(\log^2 p) worst case, often O(\log p)
* Status: Tested for all a,p <= 10000
*/
#pragma once
#include "ModPow.h"
ll sqrt(ll a, ll p) {
a %= p; if (a < 0) a += p;
if (a == 0) return 0;
assert(modpow(a, (p-1)/2, p) == 1);
if (p % 4 == 3) return modpow(a, (p+1)/4, p);
// a^(n+3)/8 or 2^(n+3)/8 * 2^(n-1)/4 works if p % 8 == 5
ll s = p - 1, n = 2;
int r = 0, m;
while (s % 2 == 0)
++r, s /= 2;
/// find a non-square mod p
while (modpow(n, (p - 1) / 2, p) != p - 1) ++n;
ll x = modpow(a, (s + 1) / 2, p);
ll b = modpow(a, s, p), g = modpow(n, s, p);
for (;; r = m) {
ll t = b;
for (m = 0; m < r && t != 1; ++m)
t = t * t % p;
if (m == 0) return x;
ll gs = modpow(g, 1LL << (r - m - 1), p);
g = gs * gs % p;
x = x * gs % p;
b = b * g % p;
}
}
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