Cualquier duda no dudes en contactar.
#include <bits/stdc++.h>
using namespace std;
struct n {
char d;
n *l;
n *r;
};
int top = -1;
n *a[20005];
void push(n *tree) {
top++;
a[top] = tree;
}
n *pop() {
top--;
return a[top + 1];
}
void construct_expression_tree(string s) {
n *newl, *p1, *p2;
for (int i = 0; i<s.length(); i++) {
if (! (s[i] == '+' || s[i] == '-' || s[i] == '*' || s[i]== '/' || s[i]== '%')) {
newl = new n;
newl->d = s[i];
newl->l = NULL;
newl->r = NULL;
push(newl);
} else {
p1 = pop();
p2 = pop();
newl = new n;
newl->d = s[i];
newl->l = p2;
newl->r = p1;
push(newl);
}
}
}
vector<char> levelOrder(n *tree){
vector<char> levels;
if (tree != NULL) {
queue<n*> pendientes;
pendientes.push(tree);
while (!pendientes.empty()) {
n *sig = pendientes.front();
pendientes.pop();
levels.push_back(sig->d);
if (sig->l != NULL)
pendientes.push(sig->l);
if (sig->r != NULL)
pendientes.push(sig->r);
}
}
return levels;
}
void inOrder(n *tree) {
if (tree != NULL) {
inOrder(tree->l);
inOrder(tree->r);
delete tree;
}
}
int main() {
string pf;
while(getline(cin,pf)) {
top = -1;
construct_expression_tree(pf);
vector<char> sol = levelOrder(a[0]);
for (int i = sol.size() -1; i >= 0; i--){
cout << sol[i];
}
printf("\n");
inOrder(a[0]);
}
return 0;
}
Sigue en contacto con Isaac Lozano Osorio!