Programación Competitiva

#include <cstdio>
#include <cmath>
using namespace std;

#define EPS 1e-9
#define PI acos(-1.0)

double DEG_to_RAD(double d) { return d * PI / 180.0; }

double RAD_to_DEG(double r) { return r * 180.0 / PI; }

struct point_i { int x, y;     // whenever possible, work with point_i
  point_i() { x = y = 0; }                      // default constructor
  point_i(int _x, int _y) : x(_x), y(_y) {} };          // constructor

struct point { double x, y;   // only used if more precision is needed
  point() { x = y = 0.0; }                      // default constructor
  point(double _x, double _y) : x(_x), y(_y) {} };      // constructor

double dist(point p1, point p2) {
  return hypot(p1.x - p2.x, p1.y - p2.y); }

double perimeter(double ab, double bc, double ca) {
  return ab + bc + ca; }

double perimeter(point a, point b, point c) {
  return dist(a, b) + dist(b, c) + dist(c, a); }

double area(double ab, double bc, double ca) {
  // Heron's formula, split sqrt(a * b) into sqrt(a) * sqrt(b); in implementation
  double s = 0.5 * perimeter(ab, bc, ca);
  return sqrt(s) * sqrt(s - ab) * sqrt(s - bc) * sqrt(s - ca); }

double area(point a, point b, point c) {
  return area(dist(a, b), dist(b, c), dist(c, a)); }

//====================================================================
// from ch7_01_points_lines
struct line { double a, b, c; }; // a way to represent a line

// the answer is stored in the third parameter (pass by reference)
void pointsToLine(point p1, point p2, line &l) {
  if (fabs(p1.x - p2.x) < EPS) {              // vertical line is fine
    l.a = 1.0;   l.b = 0.0;   l.c = -p1.x;           // default values
  } else {
    l.a = -(double)(p1.y - p2.y) / (p1.x - p2.x);
    l.b = 1.0;              // IMPORTANT: we fix the value of b to 1.0
    l.c = -(double)(l.a * p1.x) - p1.y;
} }

bool areParallel(line l1, line l2) {        // check coefficient a + b
  return (fabs(l1.a-l2.a) < EPS) && (fabs(l1.b-l2.b) < EPS); }

// returns true (+ intersection point) if two lines are intersect
bool areIntersect(line l1, line l2, point &p) {
  if (areParallel(l1, l2)) return false;            // no intersection
  // solve system of 2 linear algebraic equations with 2 unknowns
  p.x = (l2.b * l1.c - l1.b * l2.c) / (l2.a * l1.b - l1.a * l2.b);
  // special case: test for vertical line to avoid division by zero
  if (fabs(l1.b) > EPS) p.y = -(l1.a * p.x + l1.c);
  else                  p.y = -(l2.a * p.x + l2.c);
  return true; }

struct vec { double x, y;  // name: `vec' is different from STL vector
  vec(double _x, double _y) : x(_x), y(_y) {} };

vec toVec(point a, point b) {       // convert 2 points to vector a->b
  return vec(b.x - a.x, b.y - a.y); }

vec scale(vec v, double s) {        // nonnegative s = [<1 .. 1 .. >1]
  return vec(v.x * s, v.y * s); }               // shorter.same.longer

point translate(point p, vec v) {        // translate p according to v
  return point(p.x + v.x , p.y + v.y); }
//====================================================================

double rInCircle(double ab, double bc, double ca) {
  return area(ab, bc, ca) / (0.5 * perimeter(ab, bc, ca)); }

double rInCircle(point a, point b, point c) {
  return rInCircle(dist(a, b), dist(b, c), dist(c, a)); }

// assumption: the required points/lines functions have been written
// returns 1 if there is an inCircle center, returns 0 otherwise
// if this function returns 1, ctr will be the inCircle center
// and r is the same as rInCircle
int inCircle(point p1, point p2, point p3, point &ctr, double &r) {
  r = rInCircle(p1, p2, p3);
  if (fabs(r) < EPS) return 0;                   // no inCircle center

  line l1, l2;                    // compute these two angle bisectors
  double ratio = dist(p1, p2) / dist(p1, p3);
  point p = translate(p2, scale(toVec(p2, p3), ratio / (1 + ratio)));
  pointsToLine(p1, p, l1);

  ratio = dist(p2, p1) / dist(p2, p3);
  p = translate(p1, scale(toVec(p1, p3), ratio / (1 + ratio)));
  pointsToLine(p2, p, l2);

  areIntersect(l1, l2, ctr);           // get their intersection point
  return 1; }

double rCircumCircle(double ab, double bc, double ca) {
  return ab * bc * ca / (4.0 * area(ab, bc, ca)); }

double rCircumCircle(point a, point b, point c) {
  return rCircumCircle(dist(a, b), dist(b, c), dist(c, a)); }

// assumption: the required points/lines functions have been written
// returns 1 if there is a circumCenter center, returns 0 otherwise
// if this function returns 1, ctr will be the circumCircle center
// and r is the same as rCircumCircle
int circumCircle(point p1, point p2, point p3, point &ctr, double &r){
  double a = p2.x - p1.x, b = p2.y - p1.y;
  double c = p3.x - p1.x, d = p3.y - p1.y;
  double e = a * (p1.x + p2.x) + b * (p1.y + p2.y);
  double f = c * (p1.x + p3.x) + d * (p1.y + p3.y);
  double g = 2.0 * (a * (p3.y - p2.y) - b * (p3.x - p2.x));
  if (fabs(g) < EPS) return 0;

  ctr.x = (d*e - b*f) / g;
  ctr.y = (a*f - c*e) / g;
  r = dist(p1, ctr);  // r = distance from center to 1 of the 3 points
  return 1; }

// returns true if point d is inside the circumCircle defined by a,b,c
int inCircumCircle(point a, point b, point c, point d) {
  return (a.x - d.x) * (b.y - d.y) * ((c.x - d.x) * (c.x - d.x) + (c.y - d.y) * (c.y - d.y)) +
         (a.y - d.y) * ((b.x - d.x) * (b.x - d.x) + (b.y - d.y) * (b.y - d.y)) * (c.x - d.x) +
         ((a.x - d.x) * (a.x - d.x) + (a.y - d.y) * (a.y - d.y)) * (b.x - d.x) * (c.y - d.y) -
         ((a.x - d.x) * (a.x - d.x) + (a.y - d.y) * (a.y - d.y)) * (b.y - d.y) * (c.x - d.x) -
         (a.y - d.y) * (b.x - d.x) * ((c.x - d.x) * (c.x - d.x) + (c.y - d.y) * (c.y - d.y)) -
         (a.x - d.x) * ((b.x - d.x) * (b.x - d.x) + (b.y - d.y) * (b.y - d.y)) * (c.y - d.y) > 0 ? 1 : 0;
}

bool canFormTriangle(double a, double b, double c) {
  return (a + b > c) && (a + c > b) && (b + c > a); }

int main() {
  double base = 4.0, h = 3.0;
  double A = 0.5 * base * h;
  printf("Area = %.2lf\n", A);

  point a;                                         // a right triangle
  point b(4.0, 0.0);
  point c(4.0, 3.0);

  double p = perimeter(a, b, c);
  double s = 0.5 * p;
  A = area(a, b, c);
  printf("Area = %.2lf\n", A);            // must be the same as above

  double r = rInCircle(a, b, c);
  printf("R1 (radius of incircle) = %.2lf\n", r);              // 1.00
  point ctr;
  int res = inCircle(a, b, c, ctr, r);
  printf("R1 (radius of incircle) = %.2lf\n", r);        // same, 1.00
  printf("Center = (%.2lf, %.2lf)\n", ctr.x, ctr.y);   // (3.00, 1.00)

  printf("R2 (radius of circumcircle) = %.2lf\n", rCircumCircle(a, b, c)); // 2.50
  res = circumCircle(a, b, c, ctr, r);
  printf("R2 (radius of circumcircle) = %.2lf\n", r);   // same, 2.50
  printf("Center = (%.2lf, %.2lf)\n", ctr.x, ctr.y);   // (2.00, 1.50)

  point d(2.0, 1.0);               // inside triangle and circumCircle
  printf("d inside circumCircle (a, b, c) ? %d\n", inCircumCircle(a, b, c, d));
  point e(2.0, 3.9);   // outside the triangle but inside circumCircle
  printf("e inside circumCircle (a, b, c) ? %d\n", inCircumCircle(a, b, c, e));
  point f(2.0, -1.1);                              // slightly outside
  printf("f inside circumCircle (a, b, c) ? %d\n", inCircumCircle(a, b, c, f));

  // Law of Cosines
  double ab = dist(a, b);
  double bc = dist(b, c);
  double ca = dist(c, a);
  double alpha = RAD_to_DEG(acos((ca * ca + ab * ab - bc * bc) / (2.0 * ca * ab)));
  printf("alpha = %.2lf\n", alpha);
  double beta  = RAD_to_DEG(acos((ab * ab + bc * bc - ca * ca) / (2.0 * ab * bc)));
  printf("beta  = %.2lf\n", beta);
  double gamma = RAD_to_DEG(acos((bc * bc + ca * ca - ab * ab) / (2.0 * bc * ca)));
  printf("gamma = %.2lf\n", gamma);

  // Law of Sines
  printf("%.2lf == %.2lf == %.2lf\n", bc / sin(DEG_to_RAD(alpha)), ca / sin(DEG_to_RAD(beta)), ab / sin(DEG_to_RAD(gamma)));

  // Phytagorean Theorem
  printf("%.2lf^2 == %.2lf^2 + %.2lf^2\n", ca, ab, bc);

  // Triangle Inequality
  printf("(%d, %d, %d) => can form triangle? %d\n", 3, 4, 5, canFormTriangle(3, 4, 5)); // yes
  printf("(%d, %d, %d) => can form triangle? %d\n", 3, 4, 7, canFormTriangle(3, 4, 7)); // no, actually straight line
  printf("(%d, %d, %d) => can form triangle? %d\n", 3, 4, 8, canFormTriangle(3, 4, 8)); // no

  return 0;
}