Programación Competitiva

/**
 * Author: Ulf Lundstrom, Simon Lindholm
 * Date: 2009-08-15
 * License: CC0
 * Source: https://en.wikipedia.org/wiki/Tridiagonal_matrix_algorithm
 * Description: $x=\textrm{tridiagonal}(d,p,q,b)$ solves the equation system
\[
\left(\begin{array}{c}b_0\\b_1\\b_2\\b_3\\\vdots\\b_{n-1}\end{array}\right) =
\left(\begin{array}{cccccc}
d_0 & p_0 & 0 & 0 & \cdots & 0\\
q_0 & d_1 & p_1 & 0 & \cdots & 0\\
0 & q_1 & d_2 & p_2 & \cdots & 0\\
\vdots & \vdots & \ddots & \ddots & \ddots & \vdots\\
0 & 0 & \cdots & q_{n-3} & d_{n-2} & p_{n-2}\\
0 & 0 & \cdots & 0 & q_{n-2} & d_{n-1}\\
\end{array}\right)
\left(\begin{array}{c}x_0\\x_1\\x_2\\x_3\\\vdots\\x_{n-1}\end{array}\right).
\]

This is useful for solving problems on the type
\[ a_i=b_ia_{i-1}+c_ia_{i+1}+d_i,\,1\leq i\leq n, \]
where $a_0$, $a_{n+1}$, $b_i$, $c_i$ and $d_i$ are known. $a$ can then be obtained from
\begin{align*}
\{a_i\}=\textrm{tridiagonal}(&\{1,-1,-1,...,-1,1\}, \{0,c_1,c_2,\dots,c_n\},\\
&\{b_1,b_2,\dots,b_n,0\}, \{a_0,d_1,d_2,\dots,d_n,a_{n+1}\}).
\end{align*}
Fails if the solution is not unique.

If $|d_i| > |p_i| + |q_{i-1}|$ for all $i$, or $|d_i| > |p_{i-1}| + |q_i|$, or the matrix is positive definite,
the algorithm is numerically stable and neither \texttt{tr} nor the check for \texttt{diag[i] == 0} is needed.
 * Time: O(N)
 * Status: Brute-force tested mod 5 and 7 and fuzz-tested for real matrices obeying the criteria above.
 */
#pragma once

typedef double T;
vector<T> tridiagonal(vector<T> diag, const vector<T>& super,
		const vector<T>& sub, vector<T> b) {
	int n = sz(b); vi tr(n);
	FOR(i,0,n-1) {
		if (abs(diag[i]) < 1e-9 * abs(super[i])) { // diag[i] == 0
			b[i+1] -= b[i] * diag[i+1] / super[i];
			if (i+2 < n) b[i+2] -= b[i] * sub[i+1] / super[i];
			diag[i+1] = sub[i]; tr[++i] = 1;
		} else {
			diag[i+1] -= super[i]*sub[i]/diag[i];
			b[i+1] -= b[i]*sub[i]/diag[i];
		}
	}
	for (int i = n; i--;) {
		if (tr[i]) {
			swap(b[i], b[i-1]);
			diag[i-1] = diag[i];
			b[i] /= super[i-1];
		} else {
			b[i] /= diag[i];
			if (i) b[i-1] -= b[i]*super[i-1];
		}
	}
	return b;
}